コレクション cosθ=√3/2 804006-Sinθ+cosθ/sinθ-cosθ=3+2√2
Precalculus Solve for x cos (x)= ( square root of 3)/2 cos (x) = √3 2 cos ( x) = 3 2 Take the inverse cosine of both sides of the equation to extract x x from inside the cosine x = arccos( √3Take the inverse cosine of both sides of the equation to extract θ θ from inside the cosine θ = arccos(− √3 2) θ = arccos ( 3 2) Simplify the right side Tap for more steps θ = 5π 6 θ = 5 πCosθ =√5/3 Stepbystep explanation The formula for cscθ =hypotenuse/opposite cscθ =1/sinθ If cscθ =3/2 this means the hypotenuse is 3 and the opposite side value is 2Find the adjacent Solved Solve The Given Equation Enter Your Answers As A Chegg Com Sinθ+cosθ/sinθ-cosθ=3+2√2